Integrand size = 28, antiderivative size = 210 \[ \int \sec ^8(c+d x) (a \cos (c+d x)+b \sin (c+d x))^3 \, dx=\frac {3 a^3 \text {arctanh}(\sin (c+d x))}{8 d}-\frac {3 a b^2 \text {arctanh}(\sin (c+d x))}{16 d}+\frac {3 a^2 b \sec ^5(c+d x)}{5 d}-\frac {b^3 \sec ^5(c+d x)}{5 d}+\frac {b^3 \sec ^7(c+d x)}{7 d}+\frac {3 a^3 \sec (c+d x) \tan (c+d x)}{8 d}-\frac {3 a b^2 \sec (c+d x) \tan (c+d x)}{16 d}+\frac {a^3 \sec ^3(c+d x) \tan (c+d x)}{4 d}-\frac {a b^2 \sec ^3(c+d x) \tan (c+d x)}{8 d}+\frac {a b^2 \sec ^5(c+d x) \tan (c+d x)}{2 d} \]
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Time = 0.28 (sec) , antiderivative size = 210, normalized size of antiderivative = 1.00, number of steps used = 14, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {3169, 3853, 3855, 2686, 30, 2691, 14} \[ \int \sec ^8(c+d x) (a \cos (c+d x)+b \sin (c+d x))^3 \, dx=\frac {3 a^3 \text {arctanh}(\sin (c+d x))}{8 d}+\frac {a^3 \tan (c+d x) \sec ^3(c+d x)}{4 d}+\frac {3 a^3 \tan (c+d x) \sec (c+d x)}{8 d}+\frac {3 a^2 b \sec ^5(c+d x)}{5 d}-\frac {3 a b^2 \text {arctanh}(\sin (c+d x))}{16 d}+\frac {a b^2 \tan (c+d x) \sec ^5(c+d x)}{2 d}-\frac {a b^2 \tan (c+d x) \sec ^3(c+d x)}{8 d}-\frac {3 a b^2 \tan (c+d x) \sec (c+d x)}{16 d}+\frac {b^3 \sec ^7(c+d x)}{7 d}-\frac {b^3 \sec ^5(c+d x)}{5 d} \]
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Rule 14
Rule 30
Rule 2686
Rule 2691
Rule 3169
Rule 3853
Rule 3855
Rubi steps \begin{align*} \text {integral}& = \int \left (a^3 \sec ^5(c+d x)+3 a^2 b \sec ^5(c+d x) \tan (c+d x)+3 a b^2 \sec ^5(c+d x) \tan ^2(c+d x)+b^3 \sec ^5(c+d x) \tan ^3(c+d x)\right ) \, dx \\ & = a^3 \int \sec ^5(c+d x) \, dx+\left (3 a^2 b\right ) \int \sec ^5(c+d x) \tan (c+d x) \, dx+\left (3 a b^2\right ) \int \sec ^5(c+d x) \tan ^2(c+d x) \, dx+b^3 \int \sec ^5(c+d x) \tan ^3(c+d x) \, dx \\ & = \frac {a^3 \sec ^3(c+d x) \tan (c+d x)}{4 d}+\frac {a b^2 \sec ^5(c+d x) \tan (c+d x)}{2 d}+\frac {1}{4} \left (3 a^3\right ) \int \sec ^3(c+d x) \, dx-\frac {1}{2} \left (a b^2\right ) \int \sec ^5(c+d x) \, dx+\frac {\left (3 a^2 b\right ) \text {Subst}\left (\int x^4 \, dx,x,\sec (c+d x)\right )}{d}+\frac {b^3 \text {Subst}\left (\int x^4 \left (-1+x^2\right ) \, dx,x,\sec (c+d x)\right )}{d} \\ & = \frac {3 a^2 b \sec ^5(c+d x)}{5 d}+\frac {3 a^3 \sec (c+d x) \tan (c+d x)}{8 d}+\frac {a^3 \sec ^3(c+d x) \tan (c+d x)}{4 d}-\frac {a b^2 \sec ^3(c+d x) \tan (c+d x)}{8 d}+\frac {a b^2 \sec ^5(c+d x) \tan (c+d x)}{2 d}+\frac {1}{8} \left (3 a^3\right ) \int \sec (c+d x) \, dx-\frac {1}{8} \left (3 a b^2\right ) \int \sec ^3(c+d x) \, dx+\frac {b^3 \text {Subst}\left (\int \left (-x^4+x^6\right ) \, dx,x,\sec (c+d x)\right )}{d} \\ & = \frac {3 a^3 \text {arctanh}(\sin (c+d x))}{8 d}+\frac {3 a^2 b \sec ^5(c+d x)}{5 d}-\frac {b^3 \sec ^5(c+d x)}{5 d}+\frac {b^3 \sec ^7(c+d x)}{7 d}+\frac {3 a^3 \sec (c+d x) \tan (c+d x)}{8 d}-\frac {3 a b^2 \sec (c+d x) \tan (c+d x)}{16 d}+\frac {a^3 \sec ^3(c+d x) \tan (c+d x)}{4 d}-\frac {a b^2 \sec ^3(c+d x) \tan (c+d x)}{8 d}+\frac {a b^2 \sec ^5(c+d x) \tan (c+d x)}{2 d}-\frac {1}{16} \left (3 a b^2\right ) \int \sec (c+d x) \, dx \\ & = \frac {3 a^3 \text {arctanh}(\sin (c+d x))}{8 d}-\frac {3 a b^2 \text {arctanh}(\sin (c+d x))}{16 d}+\frac {3 a^2 b \sec ^5(c+d x)}{5 d}-\frac {b^3 \sec ^5(c+d x)}{5 d}+\frac {b^3 \sec ^7(c+d x)}{7 d}+\frac {3 a^3 \sec (c+d x) \tan (c+d x)}{8 d}-\frac {3 a b^2 \sec (c+d x) \tan (c+d x)}{16 d}+\frac {a^3 \sec ^3(c+d x) \tan (c+d x)}{4 d}-\frac {a b^2 \sec ^3(c+d x) \tan (c+d x)}{8 d}+\frac {a b^2 \sec ^5(c+d x) \tan (c+d x)}{2 d} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(637\) vs. \(2(210)=420\).
Time = 2.01 (sec) , antiderivative size = 637, normalized size of antiderivative = 3.03 \[ \int \sec ^8(c+d x) (a \cos (c+d x)+b \sin (c+d x))^3 \, dx=\frac {\sec ^7(c+d x) \left (10752 a^2 b+1536 b^3+3584 \left (3 a^2 b-b^3\right ) \cos (2 (c+d x))-4410 a^3 \cos (3 (c+d x)) \log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )+2205 a b^2 \cos (3 (c+d x)) \log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )-1470 a^3 \cos (5 (c+d x)) \log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )+735 a b^2 \cos (5 (c+d x)) \log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )-210 a^3 \cos (7 (c+d x)) \log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )+105 a b^2 \cos (7 (c+d x)) \log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )-3675 a \left (2 a^2-b^2\right ) \cos (c+d x) \left (\log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )-\log \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )\right )+4410 a^3 \cos (3 (c+d x)) \log \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )-2205 a b^2 \cos (3 (c+d x)) \log \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )+1470 a^3 \cos (5 (c+d x)) \log \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )-735 a b^2 \cos (5 (c+d x)) \log \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )+210 a^3 \cos (7 (c+d x)) \log \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )-105 a b^2 \cos (7 (c+d x)) \log \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )+4340 a^3 \sin (2 (c+d x))+6790 a b^2 \sin (2 (c+d x))+2800 a^3 \sin (4 (c+d x))-1400 a b^2 \sin (4 (c+d x))+420 a^3 \sin (6 (c+d x))-210 a b^2 \sin (6 (c+d x))\right )}{35840 d} \]
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Time = 1.79 (sec) , antiderivative size = 186, normalized size of antiderivative = 0.89
method | result | size |
parts | \(\frac {a^{3} \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )}{d}+\frac {b^{3} \left (\frac {\sec \left (d x +c \right )^{7}}{7}-\frac {\sec \left (d x +c \right )^{5}}{5}\right )}{d}+\frac {3 a \,b^{2} \left (\frac {\sin \left (d x +c \right )^{3}}{6 \cos \left (d x +c \right )^{6}}+\frac {\sin \left (d x +c \right )^{3}}{8 \cos \left (d x +c \right )^{4}}+\frac {\sin \left (d x +c \right )^{3}}{16 \cos \left (d x +c \right )^{2}}+\frac {\sin \left (d x +c \right )}{16}-\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{16}\right )}{d}+\frac {3 a^{2} b \sec \left (d x +c \right )^{5}}{5 d}\) | \(186\) |
derivativedivides | \(\frac {a^{3} \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )+\frac {3 a^{2} b}{5 \cos \left (d x +c \right )^{5}}+3 a \,b^{2} \left (\frac {\sin \left (d x +c \right )^{3}}{6 \cos \left (d x +c \right )^{6}}+\frac {\sin \left (d x +c \right )^{3}}{8 \cos \left (d x +c \right )^{4}}+\frac {\sin \left (d x +c \right )^{3}}{16 \cos \left (d x +c \right )^{2}}+\frac {\sin \left (d x +c \right )}{16}-\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{16}\right )+b^{3} \left (\frac {\sin \left (d x +c \right )^{4}}{7 \cos \left (d x +c \right )^{7}}+\frac {3 \sin \left (d x +c \right )^{4}}{35 \cos \left (d x +c \right )^{5}}+\frac {\sin \left (d x +c \right )^{4}}{35 \cos \left (d x +c \right )^{3}}-\frac {\sin \left (d x +c \right )^{4}}{35 \cos \left (d x +c \right )}-\frac {\left (2+\sin \left (d x +c \right )^{2}\right ) \cos \left (d x +c \right )}{35}\right )}{d}\) | \(248\) |
default | \(\frac {a^{3} \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )+\frac {3 a^{2} b}{5 \cos \left (d x +c \right )^{5}}+3 a \,b^{2} \left (\frac {\sin \left (d x +c \right )^{3}}{6 \cos \left (d x +c \right )^{6}}+\frac {\sin \left (d x +c \right )^{3}}{8 \cos \left (d x +c \right )^{4}}+\frac {\sin \left (d x +c \right )^{3}}{16 \cos \left (d x +c \right )^{2}}+\frac {\sin \left (d x +c \right )}{16}-\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{16}\right )+b^{3} \left (\frac {\sin \left (d x +c \right )^{4}}{7 \cos \left (d x +c \right )^{7}}+\frac {3 \sin \left (d x +c \right )^{4}}{35 \cos \left (d x +c \right )^{5}}+\frac {\sin \left (d x +c \right )^{4}}{35 \cos \left (d x +c \right )^{3}}-\frac {\sin \left (d x +c \right )^{4}}{35 \cos \left (d x +c \right )}-\frac {\left (2+\sin \left (d x +c \right )^{2}\right ) \cos \left (d x +c \right )}{35}\right )}{d}\) | \(248\) |
parallelrisch | \(\frac {-210 \left (a^{2}-\frac {b^{2}}{2}\right ) a \left (\cos \left (7 d x +7 c \right )+7 \cos \left (5 d x +5 c \right )+21 \cos \left (3 d x +3 c \right )+35 \cos \left (d x +c \right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )+210 \left (a^{2}-\frac {b^{2}}{2}\right ) a \left (\cos \left (7 d x +7 c \right )+7 \cos \left (5 d x +5 c \right )+21 \cos \left (3 d x +3 c \right )+35 \cos \left (d x +c \right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+\left (7056 a^{2} b -672 b^{3}\right ) \cos \left (3 d x +3 c \right )+\left (2352 a^{2} b -224 b^{3}\right ) \cos \left (5 d x +5 c \right )+\left (336 a^{2} b -32 b^{3}\right ) \cos \left (7 d x +7 c \right )+\left (10752 a^{2} b -3584 b^{3}\right ) \cos \left (2 d x +2 c \right )+\left (4340 a^{3}+6790 a \,b^{2}\right ) \sin \left (2 d x +2 c \right )+\left (2800 a^{3}-1400 a \,b^{2}\right ) \sin \left (4 d x +4 c \right )+\left (420 a^{3}-210 a \,b^{2}\right ) \sin \left (6 d x +6 c \right )+\left (11760 a^{2} b -1120 b^{3}\right ) \cos \left (d x +c \right )+10752 a^{2} b +1536 b^{3}}{560 d \left (\cos \left (7 d x +7 c \right )+7 \cos \left (5 d x +5 c \right )+21 \cos \left (3 d x +3 c \right )+35 \cos \left (d x +c \right )\right )}\) | \(361\) |
risch | \(-\frac {{\mathrm e}^{i \left (d x +c \right )} \left (-210 i a^{3}+3395 i a \,b^{2} {\mathrm e}^{8 i \left (d x +c \right )}+210 i a^{3} {\mathrm e}^{12 i \left (d x +c \right )}+2170 i a^{3} {\mathrm e}^{8 i \left (d x +c \right )}-700 i a \,b^{2} {\mathrm e}^{10 i \left (d x +c \right )}-3395 i a \,b^{2} {\mathrm e}^{4 i \left (d x +c \right )}-5376 a^{2} b \,{\mathrm e}^{8 i \left (d x +c \right )}+1792 b^{3} {\mathrm e}^{8 i \left (d x +c \right )}-10752 a^{2} b \,{\mathrm e}^{6 i \left (d x +c \right )}-1536 b^{3} {\mathrm e}^{6 i \left (d x +c \right )}+105 i a \,b^{2}+1400 i a^{3} {\mathrm e}^{10 i \left (d x +c \right )}-5376 a^{2} b \,{\mathrm e}^{4 i \left (d x +c \right )}+1792 b^{3} {\mathrm e}^{4 i \left (d x +c \right )}+700 i a \,b^{2} {\mathrm e}^{2 i \left (d x +c \right )}-2170 i a^{3} {\mathrm e}^{4 i \left (d x +c \right )}-1400 i a^{3} {\mathrm e}^{2 i \left (d x +c \right )}-105 i a \,b^{2} {\mathrm e}^{12 i \left (d x +c \right )}\right )}{280 d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{7}}+\frac {3 a^{3} \ln \left (i+{\mathrm e}^{i \left (d x +c \right )}\right )}{8 d}-\frac {3 a \,b^{2} \ln \left (i+{\mathrm e}^{i \left (d x +c \right )}\right )}{16 d}-\frac {3 a^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )}{8 d}+\frac {3 a \,b^{2} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )}{16 d}\) | \(405\) |
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Time = 0.27 (sec) , antiderivative size = 170, normalized size of antiderivative = 0.81 \[ \int \sec ^8(c+d x) (a \cos (c+d x)+b \sin (c+d x))^3 \, dx=\frac {105 \, {\left (2 \, a^{3} - a b^{2}\right )} \cos \left (d x + c\right )^{7} \log \left (\sin \left (d x + c\right ) + 1\right ) - 105 \, {\left (2 \, a^{3} - a b^{2}\right )} \cos \left (d x + c\right )^{7} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 160 \, b^{3} + 224 \, {\left (3 \, a^{2} b - b^{3}\right )} \cos \left (d x + c\right )^{2} + 70 \, {\left (3 \, {\left (2 \, a^{3} - a b^{2}\right )} \cos \left (d x + c\right )^{5} + 8 \, a b^{2} \cos \left (d x + c\right ) + 2 \, {\left (2 \, a^{3} - a b^{2}\right )} \cos \left (d x + c\right )^{3}\right )} \sin \left (d x + c\right )}{1120 \, d \cos \left (d x + c\right )^{7}} \]
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Timed out. \[ \int \sec ^8(c+d x) (a \cos (c+d x)+b \sin (c+d x))^3 \, dx=\text {Timed out} \]
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Time = 0.22 (sec) , antiderivative size = 208, normalized size of antiderivative = 0.99 \[ \int \sec ^8(c+d x) (a \cos (c+d x)+b \sin (c+d x))^3 \, dx=\frac {35 \, a b^{2} {\left (\frac {2 \, {\left (3 \, \sin \left (d x + c\right )^{5} - 8 \, \sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{6} - 3 \, \sin \left (d x + c\right )^{4} + 3 \, \sin \left (d x + c\right )^{2} - 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 70 \, a^{3} {\left (\frac {2 \, {\left (3 \, \sin \left (d x + c\right )^{3} - 5 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + \frac {672 \, a^{2} b}{\cos \left (d x + c\right )^{5}} - \frac {32 \, {\left (7 \, \cos \left (d x + c\right )^{2} - 5\right )} b^{3}}{\cos \left (d x + c\right )^{7}}}{1120 \, d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 465 vs. \(2 (190) = 380\).
Time = 0.41 (sec) , antiderivative size = 465, normalized size of antiderivative = 2.21 \[ \int \sec ^8(c+d x) (a \cos (c+d x)+b \sin (c+d x))^3 \, dx=\frac {105 \, {\left (2 \, a^{3} - a b^{2}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right ) - 105 \, {\left (2 \, a^{3} - a b^{2}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right ) + \frac {2 \, {\left (350 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{13} + 105 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{13} - 1680 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{12} - 840 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} + 1540 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} + 3360 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{10} - 1120 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{10} + 630 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 1085 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} - 5040 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{8} - 1120 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{8} + 6720 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} - 2240 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} - 630 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 1085 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 3696 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 448 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 840 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 1540 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 672 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 224 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 350 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 105 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 336 \, a^{2} b + 32 \, b^{3}\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{7}}}{560 \, d} \]
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Time = 26.80 (sec) , antiderivative size = 423, normalized size of antiderivative = 2.01 \[ \int \sec ^8(c+d x) (a \cos (c+d x)+b \sin (c+d x))^3 \, dx=\frac {3\,a\,\mathrm {atanh}\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )\,\left (2\,a^2-b^2\right )}{8\,d}-\frac {\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (\frac {5\,a^3}{4}+\frac {3\,a\,b^2}{8}\right )+\frac {6\,a^2\,b}{5}+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,\left (\frac {11\,a\,b^2}{2}-3\,a^3\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}\,\left (\frac {11\,a\,b^2}{2}-3\,a^3\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{13}\,\left (\frac {5\,a^3}{4}+\frac {3\,a\,b^2}{8}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5\,\left (\frac {9\,a^3}{4}+\frac {31\,a\,b^2}{8}\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9\,\left (\frac {9\,a^3}{4}+\frac {31\,a\,b^2}{8}\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}\,\left (12\,a^2\,b-4\,b^3\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\left (\frac {12\,a^2\,b}{5}-\frac {4\,b^3}{5}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8\,\left (18\,a^2\,b+4\,b^3\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6\,\left (24\,a^2\,b-8\,b^3\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,\left (\frac {66\,a^2\,b}{5}+\frac {8\,b^3}{5}\right )-\frac {4\,b^3}{35}+6\,a^2\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{14}-7\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}+21\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}-35\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8+35\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6-21\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+7\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2-1\right )} \]
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